posted on Aug, 12 2014 @ 09:55 PM
There is nothing even coincidental about these types of calculations. You could use a variant of all those phrases, names of people, etc, to arrive at
any number you wanted to. Not to mention the fact that when using ancient names in a modern context the spelling changes completely, and thus the
numerical values. It is a bunch of hogwash, of that I am certain.
If you want a numerical challenge, I have encoded a secret message. See if you can decrypt it. (It really is encoded, but you cannot decrypt it, even
though I did it by hand and it is not a computer-level encryption.) 9A 61 EB 23 4B
41 C1 52 EB 22 A1 42 11 2B 6C 92 91 IB 5B 6A 21 I1 42 22 AA 41 E1 4B FB 91 C1 I2 11 13 43 DC 4C DA 52 AC 43 81 11 AC 82
5A AA 22 B2 63 H1 A1 62 FB 5A 42 EA 41 D1 52 13 31 52 CB 92 22 AA 9B HA 4C H2 81 1A HB A3 I1 3A 22 51 92
IB B2 1A 9B H1 71 11 2B B2 E1 HB F3 E2 61 FA 11 12 51 21 IA 4B 2B AA 41 5A 42 92 4A EB 13 62 H1 FB
I suppose you MIGHT be able to get it if I tell you that it is a one-time pad, and that the key is what everyone has sitting in front of them at the
moment. And after the OTP has been encrypted, the letters and numerals you see in the above cipher are simply the same as the key, but arranged on a
graph. So the OTP encryption was converted to what you see above. Now it is much easier. If the key were random it would unbreakable, even with a
super computer.